Week 7-Long Piston With Cam

LONG PISTON WITH CAM CHALLENGE

OBJECTIVES

            In this challenge, we have to perform a transient analysis on a piston and cam mechanism model that has been provided to you. You need to run the analysis with Frictionless contact, Frictional with 0.1 and 0.2 as the frictional contact for a total of 3 cases. Find out the Equivalent Stress, Directional Deformation and Equivalent Elastic Strain and compare them for all the three cases. Give an inference as to why the results vary between cases.

PROCEDURE

• First, we have to input the engineering materials with required properties or else by creating with required properties.

• Then we have to import our model into ansys, import the model and open it in space claim so that ansys will read it.

• Make the cam and barrel stiffness as rigid as we will not concentrate on that components.

• Then assign required connections in this assignment we will use frictionless contact between the components for case 1 and frictional contact between the components for case 2&3 revolute joint at for the cam, then body-body tranlation joint between cam follower and barrel and finally make the barrel as fixed.

Then mesh the component with required mesh size in this assignment we will use

• Mesh – default
• Sizing – 3mm
• Nodes – 2901
• Elements – 1082

• Analysis setting then assign revolute joint load and translation load.

• Then give the required solution parameters then solve.

RESULTS

Case1 – Frictionless

Directional Deformation

Equivalent stress

Equivalent strain

Total Acceleration

Contact Pressure

Case2 – Frictional 0.1

Directional Deformation

Equivalent stress

Equivalent strain

Total Acceleration

Contact Pressure

 

Case1 – Frictional 0.3

Directional Deformation

Equivalent stress

 

Equivalent strain

Total Acceleration

Contact Pressure

CONCLUSION

	Directional Deformation (mm)	Equivalent strain	Equivalent stress (MPa)	Contact Pressure (MPa)
Case 1	20.372	0.008829	1756.6	1329.8
Case 2	20.513	0.00959	1849	1285.4
Case 3	20.551	0.01210	2339.3	1374.2

 

From the above stimulation result it is clearly understand that if coefficient of friction increases the stress and strain also increases because the frictional force always act on opposite direction of the motion and cause restiction to motion.