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  1. Home/
  2. ARAVIND M/
  3. Week 3 Sheet metal Bending challenge

Week 3 Sheet metal Bending challenge

SHEET METAL BENDING OBJECTIVES             In this challenges Sheet metal bending is to be performed for 3 different materials mentioned below. Variation of certain settings is also to be performed and your conclusions are to be added to the report Run the analysis…

    • ARAVIND M

      updated on 23 Aug 2020

    SHEET METAL BENDING

    OBJECTIVES

                In this challenges Sheet metal bending is to be performed for 3 different materials mentioned below. Variation of certain settings is also to be performed and your conclusions are to be added to the report

    Run the analysis for the material :

    Case 1:Aluminium Alloy 1199( mentioned in the course video),Copper Alloy NL and Magnesium Alloy NL. Find out the Equivalent stress, Equivalent elastic strain and Total Deformation in Y direction and compare the results for the three materials.

    Case 2:With the material as Aluminium Alloy, change the friction coefficient to 0.19 and run the analysis as mentioned in Case 1. Compare the results with that in case 1.

    Case 3: Refine the mesh on the plate such that it doesn't cross the academic limit. With Aluminium alloy as material, run the analysis as in Case 1 and compare the results.

    PROCEDURE

    • First, we have to input the engineering materials with required properties or else by creating with required properties.

     

    • Then we have to import our model into ansys, import the model and open it in space claim so that ansys will read it.

    • Then assign required connections in this assignment we will use frictional contact between the components.

    • Then mesh the component with required mesh size in this assignment we will use
      • Mesh       â€“ 4mm
      • Sizing      â€“ 1mm tetrahedrone
      • Nodes      – 22708
      • Elements  – 7318

    • Analysis setting

    • Then give the required solution parameters then solve .

    CASE1: Aluminium Alloy 1199( mentioned in the course video),Copper Alloy NL and Magnesium Alloy NL. Find out the Equivalent stress, Equivalent elastic strain and Total Deformation in Y direction and compare the results for the three materials.

    Aluminium Alloy 1199

    Directional deformation at Y- Axis

    Equivalent stress

    Equivalent stress at plate

    Equivalent elastic strain

    Copper Alloy NL

    Directional deformation at Y- Axis

    Equivalent stress

     

    Equivalent stress at plate

    Equivalent elastic strain

    Magnesium Alloy NL

    Directional deformation at Y- Axis

    Equivalent stress

    Equivalent stress at plate

    Equivalent elastic strain

    Result

      Deformation at Y-axis (mm) Equivalent strain stress on plate (MPa)
    Aluminium 1199

    3.684

    2.8319

    191.3

    Magnesium NL 3.74 2.472 270.432
    Copper NL 3.697 2.7267 387.58

    copper has more ductility than other materials hence the stress is more in copper.

    Magnesium has more deformation on Y-Axis

    while elastic strain aluminium has maximum strain.

    Case 2: With the material as Aluminium Alloy, change the friction coefficient to 0.19 and run the analysis as mentioned in Case 1. Compare the results with that in case 1.

    Directional deformation at Y- Axis

    Equivalent stress

    Equivalent stress at plate

    Equivalent elastic strain

    Result

      Deformation at Y-axis (mm) Equivalent strain stress on plate (MPa)
    Aluminium 1199

    3.684

    2.8319

    191.3

    Case 2 3.743 1.487 269.21

    While increasing the frictional coefficinet to 0.19 the elastic strain reduces.

    Case 3: Refine the mesh on the plate such that it doesn't cross the academic limit. With Aluminium alloy as material, run the analysis as in Case 1 and compare the results.

    • Mesh       â€“ 4mm
    • Sizing      â€“ 0.9mm tetrahedrone
    • Nodes      – 28424
    • Elements  – 9868

    Directional deformation at Y- Axis

    Equivalent stress

     

    Equivalent stress at plate

    Equivalent elastic strain

     

    Result

     

      Deformation at Y-axis (mm) Equivalent strain stress on plate (MPa)
    Aluminium 1199

    3.684

    2.8319

    191.3

    Case 2 3.644 3.17 186.36

     While reducing the mesh size the result will be more accurate but the computational time will be more.

     CONCLUSION

    Finally the bending of sheet metal is performed with different case sinarior and result is solved.

     

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