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AIM To understand powertrain for aircraft in runways. PROBLEM SPECIFICATION AND SOLVING: PROBLEM STATEMENT I: Search and list out the total weight of various types of aircrafts. EXPLANATION AND OBSERVATION: [1] There are many factors that lead to efficient and safe operation of aircraft. Among these vital factors are proper…
Laasya Priya Nidamarty
updated on 17 May 2021
To understand powertrain for aircraft in runways.
Search and list out the total weight of various types of aircrafts.
EXPLANATION AND OBSERVATION:
MDLW < MDTOW < MDTW
Maximum payload = MDZFW – OEW
MEW |
Not MEW |
Airframe structure with all moving mechanical parts (fuselage, wings, flaps, gear, rudder, nacelle …) |
Fuel |
Power generation system (APU, main engines, power plant…) |
Oil, potable water |
Systems (electrical, hydraulics, pneumatic, fuel flow system, instrument, navigation, air conditioning, anti-ice, fixed furnishing) |
Payload (Cargo, passenger, luggage) |
Fixed equipment and services considered an integral part of the aircraft |
Removable equipment |
Fixed ballast |
Customer specific installations or operator items |
Closed system fluids |
Fuel |
Unused fuel only for small aircraft |
Oil, potable water |
Table 1. Weights that constitute MEW and which does not.
S.No |
Operator’s weight |
1 |
fluids necessary for aircraft operation (engine oil and coolant, water, unusable fuel) |
2 |
the water for galleys and lavatories |
3 |
aircraft documentation |
4 |
passenger seats (and the life vests) |
5 |
galley structure |
6 |
catering emergency equipment |
7 |
aircraft crew and their luggage. |
8 |
standard items necessary for full operation |
Table 2. List constituting OEW.
Type |
MTOW [kg] |
MLW [tonnes] |
TOR [m] |
LR [m] |
ICAO category |
FAA category |
Antonov An-225 |
640,000 |
591.7 |
3500 |
Heavy |
Super |
|
Scaled Composites Model 351 Stratolaunch |
589,670 |
3660 |
Heavy |
Super |
||
Airbus A380-800 |
575,000 |
394 |
3100 |
1930 |
Super |
Super |
Boeing 747-8F |
447,700 |
346.091 |
3100 |
1800 |
Heavy |
Heavy |
Boeing 747-8 |
443,613 |
306.175 |
3100 |
Heavy |
Heavy |
|
Boeing 747-400ER |
412,770 |
295.742 |
3090 |
Heavy |
Heavy |
|
Antonov An-124-100M |
405,060 |
330 |
2520 |
900 |
Heavy |
Heavy |
Boeing 747-400 |
396,900 |
295.742 |
3018 |
2179 |
Heavy |
Heavy |
Lockheed C-5 Galaxy |
381,000 |
288.417 |
2530 |
1494 |
Heavy |
Heavy |
Boeing 747-200 |
377,840 |
285.700 |
3338 |
2109 |
Heavy |
Heavy |
Boeing 747-300 |
377,840 |
260.320 |
3222 |
1905 |
Heavy |
Heavy |
Airbus A340-500 |
371,950 |
240 |
3050 |
2010 |
Heavy |
Heavy |
Airbus A340-600 |
367,400 |
256 |
3100 |
2100 |
Heavy |
Heavy |
Boeing 777F |
347,800 |
260.816 |
2830 |
Heavy |
Heavy |
|
Airbus A330-900 |
352,000 |
251.5 |
3100 |
Heavy |
Heavy |
|
Boeing 777-300ER |
351,800 |
251.29 |
3100 |
Heavy |
Heavy |
|
Boeing 777-200LR |
347,450 |
223.168 |
3000 |
Heavy |
Heavy |
|
Boeing 747-100 |
340,200 |
265.300 |
Heavy |
Heavy |
||
Airbus A350-1000 |
308,000 |
233.5 |
Heavy |
Heavy |
||
Boeing 777-300 |
299,370 |
237.683 |
3380 |
Heavy |
Heavy |
|
Boeing 777-200ER |
297,550 |
213.00 |
3380 |
1550 |
Heavy |
Heavy |
Airbus A340-300 |
276,700 |
190 |
3000 |
1926 |
Heavy |
Heavy |
McDonnell Douglas MD-11 |
273,300 |
185 |
2990 |
1890 |
Heavy |
Heavy |
Airbus A350-900 |
270,000 |
175 |
2670 |
1860 |
Heavy |
Heavy |
Ilyushin Il-96M |
270,000 |
195.04 |
3115 |
2118 |
Heavy |
Heavy |
McDonnell Douglas DC-10 |
256,280 |
183 |
2990 |
1890 |
Heavy |
Heavy |
Boeing 787-9 |
254,000 |
192.777 |
2900 |
Heavy |
Heavy |
|
Boeing 787-10 |
254,000 |
201.849 |
Heavy |
Heavy |
||
Airbus A340-200 |
253,500 |
181 |
2990 |
Heavy |
Heavy |
|
Ilyushin IL-96-300 |
250,000 |
175 |
2600 |
1980 |
Heavy |
Heavy |
Airbus A330-300 |
242,000 |
185 |
2500 |
1750 |
Heavy |
Heavy |
Airbus A330-200 |
242,000 |
180 |
2220 |
1750 |
Heavy |
Heavy |
Lockheed L-1011-500 |
231,300 |
166.92 |
2636 |
Heavy |
Heavy |
|
Boeing 787-8 |
228,000 |
172.365 |
3300 |
1695 |
Heavy |
Heavy |
Lockheed L-1011-200 |
211,400 |
Heavy |
Heavy |
|||
Ilyushin IL-86 |
208,000 |
175 |
Heavy |
Heavy |
||
Boeing 767-400ER |
204,000 |
158.758 |
3414 |
Heavy |
Heavy |
|
Airbus A300-600R |
192,000 |
140 |
2385 |
1555 |
Heavy |
Heavy |
Boeing 767-300ER |
187,000 |
136.08 |
2713 |
1676 |
Heavy |
Heavy |
Concorde |
185,000 |
111.1 |
3440 |
2220 |
Heavy |
Heavy |
Airbus A300-600 |
163,000 |
138 |
2324 |
1536 |
Heavy |
Heavy |
Boeing 767-300 |
159,000 |
136.078 |
2713 |
1676 |
Heavy |
Heavy |
Airbus A310-300 |
157,000 |
124 |
2290 |
1490 |
Heavy |
Heavy |
Vickers VC10 |
152,000 |
151.9 |
Heavy |
Heavy |
||
Boeing 707-320B |
151,000 |
97.5 |
Heavy |
Heavy |
||
Boeing 707-320C |
151,000 |
112.1 |
Heavy |
Heavy |
||
Douglas DC-8-61 |
147,000 |
Heavy |
Heavy |
|||
Airbus A310-200 |
142,000 |
123 |
1860 |
1480 |
Heavy |
Heavy |
Airbus A400M |
141,000 |
122 |
980 |
770 |
Heavy |
Heavy |
Douglas DC-8-32 |
140,000 |
Heavy |
Heavy |
|||
Douglas DC-8-51 |
125,000 |
Medium |
Large |
|||
Boeing 757-300 |
124,000 |
101.6 |
2550 |
1750 |
Medium |
Large |
Boeing 707-120B |
117,000 |
86.3 |
Medium |
Large |
||
Boeing 757-200 |
116,000 |
89.9 |
2347 |
1555 |
Medium |
Large |
Boeing 720B |
106,000 |
79.5 |
Medium |
Large |
||
Boeing 720 |
104,000 |
79.5 |
Medium |
Large |
||
Tupolev Tu-154M |
104,000 |
80 |
Medium |
Large |
||
Tupolev Tu-204SM |
104,000 |
87.5 |
2250 |
Medium |
Large |
|
Convair 880 |
87,500 |
Medium |
Large |
|||
Boeing 737-900 |
85,000 |
66.36 |
2500 |
1704 |
Medium |
Large |
Boeing 737-900ER |
85,000 |
71.35 |
2804 |
1829 |
Medium |
Large |
Boeing 727-200 Advanced |
84,000 |
70.1 |
Medium |
Large |
||
Airbus A321-100 |
83,000 |
77.8 |
2200 |
1540 |
Medium |
Large |
Boeing 737-800 |
79,000 |
65.32 |
2308 |
1634 |
Medium |
Large |
Boeing 727-200 |
78,000 |
68.1 |
Medium |
Large |
||
McDonnell-Douglas MD-83 |
73,000 |
63.28 |
Medium |
Large |
||
Boeing 727-100 |
72,500 |
62.4 |
Medium |
Large |
||
Boeing 727-100C |
72,500 |
62.4 |
Medium |
Large |
||
McDonnell-Douglas MD-90-30 |
71,000 |
64.41 |
2165 |
1520 |
Medium |
Large |
de Havilland Comet 4 |
70,700 |
Medium |
Large |
|||
Boeing 737-700 |
70,000 |
58.06 |
1921 |
1415 |
Medium |
Large |
Airbus A320-100 |
68,000 |
66 |
1955 |
1490 |
Medium |
Large |
Boeing 737-400 |
68,000 |
54.9 |
2540 |
1540 |
Medium |
Large |
de Havilland Comet 3 |
68,000 |
Medium |
Large |
|||
Boeing 377 |
67,000 |
Medium |
Large |
|||
Boeing 737-600 |
66,000 |
54.66 |
1796 |
1340 |
Medium |
Large |
Airbus A220-300 |
65,000 |
57.61 |
1890 |
1494 |
Medium |
Large |
Hawker Siddeley Trident 2E |
65,000 |
Medium |
Large |
|||
Airbus A319 |
64,000 |
62.5 |
1850 |
1470 |
Medium |
Large |
Boeing 737-300 |
63,000 |
51.7 |
1939 |
1396 |
Medium |
Large |
Boeing 737-500 |
60,000 |
49.9 |
1832 |
1360 |
Medium |
Large |
Airbus A220-100 |
59,000 |
50.80 |
1463 |
1356 |
Medium |
Large |
Airbus A318 |
59,000 |
57.5 |
1375 |
1340 |
Medium |
Large |
Boeing 717-200HGW |
55,000 |
47.174 |
1950 |
Medium |
Large |
|
Douglas DC-7 |
55,000 |
Medium |
Large |
|||
de Havilland Comet 2 |
54,000 |
Medium |
Large |
|||
Boeing 717-200BGW |
50,000 |
46.265 |
1950 |
Medium |
Large |
|
de Havilland Comet 1 |
50,000 |
Medium |
Large |
|||
Douglas DC-6A |
48,600 |
Medium |
Large |
|||
Douglas DC-6B |
48,500 |
Medium |
Large |
|||
Embraer 190 |
48,000 |
43 |
2056 |
1323 |
Medium |
Large |
Caravelle III |
46,000 |
Medium |
Large |
|||
Fokker 100 |
46,000 |
39.95 |
1621 |
1350 |
Medium |
Large |
Douglas DC-6 |
44,000 |
Medium |
Large |
|||
Avro RJ-85 |
42,000 |
36.74 |
Medium |
Large |
||
Handley Page Hermes |
39,000 |
Medium |
Large |
|||
Embraer 175 |
37,500 |
32.8 |
2244 |
1304 |
Medium |
Large |
Bombardier CRJ900 |
36,500 |
33.345 |
1778 |
1596 |
Medium |
Large |
Embraer 170 |
36,000 |
32.8 |
1644 |
1274 |
Medium |
Large |
Bombardier CRJ700 |
33,000 |
30.39 |
1564 |
1478 |
Medium |
Large |
Douglas DC-4 |
33,000 |
Medium |
Large |
|||
Vickers Viscount 800 |
30,400 |
Medium |
Large |
|||
Bombardier Q400 |
28,000 |
28.01 |
1219 |
1295 |
Medium |
Large |
Bombardier CRJ200 |
23,000 |
21.319 |
1918 |
1479 |
Medium |
Large |
ATR 72-600 |
22,800 |
22.35 |
1333 |
914 |
Medium |
Large |
Saab 2000 |
22,800 |
21.5 |
1300 |
Medium |
Large |
|
Embraer ERJ 145 |
22,000 |
19.3 |
2270 |
1380 |
Medium |
Large |
ATR 42-500 |
18,600 |
18.3 |
1165 |
1126 |
Medium |
Small |
Saab 340 |
13,150 |
12.930 |
1300 |
1030 |
Medium |
Small |
Embraer 120 Brasilia |
11,500 |
11.25 |
1560 |
1380 |
Medium |
Small |
BAe Jetstream 41 |
10,890 |
10.570 |
1493 |
826 |
Medium |
Small |
Learjet 75 |
9,752 |
8.709 |
1353 |
811 |
Medium |
Small |
Pilatus PC-24 |
8,300 |
7.665 |
893 |
724 |
Medium |
Small |
Embraer Phenom 300 |
8,150 |
7.65 |
956 |
677 |
Medium |
Small |
Beechcraft 1900D |
7,765 |
7.605 |
1036 |
853 |
Medium |
Small |
Cessna Citation CJ4 |
7,761 |
7.103 |
1039 |
896 |
Medium |
Small |
de Havilland Hercules |
7,000 |
Medium |
Small |
|||
Embraer Phenom 100 |
4,800 |
4.43 |
975 |
741 |
Light |
Small |
Table 3. List of the aircraft sorted by maximum takeoff weight.
Is there any difference between ground speed and air speed?
EXPLANATION AND OBSERVATION:
Figure 1. Relative Velocities.
Airspeed = Ground Speed - Wind Speed
Why is it not recommended to use aircraft engine power to move it on the ground at Airport?
EXPLANATION AND OBSERVATION:
Figure 2. Jet airliners taxiing.
How is an aircraft pushed to runway when its ready to take off?
EXPLANATION AND OBSERVATION:
PROCEDURE:
Figure 3. Figure showing pushback truck pushing the aircraft.
EQUIPMENT USED FOR PUSHBACK:
Figure 4. Light aircraft can usually be moved by human power alone. Here, this Aerotechnik EV-97A Eurostar is being pulled into position for refueling.
Figure 5. A conventional tractor hooked up to a United Airlines Boeing 777-200ER at Denver International Airport.
Figure 6. Towbars are used to connect the tractor to the aircraft..
Figure 7. A towbarless tug at Frankfurt Airport transporting a Lufthansa Airbus A340-300.
Learn about take-off power, tyre design, rolling resistance, tyre pressure, brake forces when landing.
EXPLANATION AND OBSERVATION:
The take-off flight is generally divided into three phases namely: ground run, transition(or flare) and climb.[7]
Figure 8. Phases of Take-Off flight.
From the point of view of performance analysis, the following two quantities are of interest.
(i) The take-off distance (s) (ii) The time (t) taken for it.
The equations of motion for the aircraft under consideration are as follows:
Where, T is the thrust force, D is the drag force, R is the reaction force and W is the weight of the aircraft. Using equilibrium conditions, the reaction force R is calculated as:
Where L si the lift force.
The take off power can be calculated using the thrust component of force which is rewritten as:
The forces acting on the airplane are shown in Figure 8. It is observed that the ground reaction (R) and the rolling friction, μ R, are the two additional forces along with the lift, the drag, the weight and thrust ; μ is the coefficient of rolling friction between the runway and the landing gear wheels. The value of µ depends on the type of surface. The angle of attack and hence, the lift coefficient (CL ) and the drag coefficient (CD ) can be assumed to remain constant during the take-off run.
The equation for the ground run (s1) is given as:
The time taken for the ground run (s1) is given as:
[8] For light aircraft, usually full power is used during takeoff. Large transport category (airliner) aircraft may use a reduced power for takeoff, where less than full power is applied in order to prolong engine life, reduce maintenance costs, and reduce noise emissions. In some emergency cases, the power used can then be increased to increase the aircraft's performance. Before takeoff, the engines, particularly piston engines, are routinely run up at high power to check for engine-related problems. The aircraft is permitted to accelerate to rotation speed.
[9] The amount of power that an engine is allowed to produce for a limited period of time for takeoff is called Take-Off Power. The use of takeoff power is usually limited to 5 min for reciprocating engines and up to 2½ min for gas turbine engines. This may not always be the case. Specifically, with respect to reciprocating engines, it is the brake horsepower developed under standard, sea-level conditions and under the maximum conditions of the crankshaft rotational speed and the engine manifold pressure approved for the normal take-off. It is limited in continuous use to the period of time shown in the approved engine specifications. With respect to gas turbine engines, it is the thrust developed under static conditions at a specified altitude and atmospheric conditions of the rotor shaft rotational speed and gas temperature approved for the normal takeoff. It is limited in continuous use to the period of time shown in the approved engine specifications.
Figure 9. Description of an aircraft tyre.
The technical aspects of the tyre are as follows:
Aircraft tyres must have an approved speed and load rating and have sufficient clearance when retracted through landing gear to allow for tyre growth. Tyre growth is the increase in the size of the tyre due to centrifugal forces at high speed. Tubeless tyres are more advantageous over tube-type. There is no longer the use of tube-type tyre in recent aviation. Nowadays all airliners are using tubeless tyres. Tubeless that are meant to be used without a tube has the word TUBELESS on the sidewall of the tyre. Almost all airliners are using Radial tyre. Bias is an older design, and it’s mainly used for road vehicles. Radial tyres have the word RADIAL on the sidewall. Radial tires are more expensive than bias-ply tyres. Radial tires are in demand because of their lower life cycle cost and long-term value.
Aircraft tyres are manufactured with tread rubber with conducting compounds to permit earthing of static charges. In early days, when tyres were not sufficiently conductive, aircraft used to have a conductive strip hanging down from the axle of the landing gear. Upon landing, this strip would be the first part of the aircraft to touch the earth. This discharges any static electricity accumulated on the outer surfaces of the aircraft, which is not the case anymore.
Chines are also called deflectors. Chine tyre used on the nose wheel of aircraft, specially fuselage-mounted jet engines. It diverts runway water away from the engine inlets. Chines are circumferential protrusions that are moulded into the sidewall of nose tyres that deflect water sideways to help reduce excess water ingestion into the engines. Tyres may have chines on one or both sides, depending on the number of nose tyres on the aircraft.
Figure 10. Tyre showcasing chine.
[11] An aircraft tire or tyre is designed to withstand extremely heavy loads for short durations. The number of tires required for aircraft increases with the weight of the aircraft, as the weight of the airplane needs to be distributed more evenly. Aircraft tire tread patterns are designed to facilitate stability in high crosswind conditions, to channel water away to prevent hydroplaning, and for braking effect. Aircraft tires also include fusible plugs (which are assembled on the inside of the wheels), designed to melt at a certain temperature. Tires often overheat if maximum braking is applied during an aborted takeoff or an emergency landing. The fuses provide a safer failure mode that prevents tire explosions by deflating in a controlled manner, thus minimizing damage to aircraft and objects in the surrounding environment.
The following result is obtained in the field experiments which include courses of wheel forces and moments acting on the left wheel of the Wilga airplane. Figure 11(a,b) shows an example of horizontal force, FX, which is input data for calculations (upper graph) and the rolling resistance coefficient, kRR (lower graph), value determined using equation of the rolling resistance mentioned above. Average values are marked on the graphs (FX = 1719 N and kRR = 0.275). When determining the kRR coefficient, it is important to correctly select a portion of the FX force waveform. Namely, it is a fragment where the waveform is determined (in Figure 11(a,b), up, this fragment begins after the first second of the wave).
Figure 11 (a) Sample courses of the measured horizontal force, FX, and calculated rolling resistance coefficient, kRR.
Figure 11 (b) Calculated rolling resistance coefficient, kRR.
Figure 12. below compares key parameters between a passenger car tire and two aircraft tires of about the same dimensions.
Additionally, the passenger car and truck tires are able to operate continuously because they reach thermal equilibrium while aircraft tires do not. An aircraft tire which taxis continuously at rated load and 40 mph will continue to heat up until the tire fails. The failure to reach thermal equilibrium is a consequence of the high deflections (the difference between the unloaded and loaded tire section height) at which aircraft tires operate. High inflation pressure and high deflection rates – 2.5 times greater than a car tire – allow relatively small tires to support the high loads of an aircraft.
Because aircraft tires operate at such high extremes of pressure, load, and speed, their care and service is critically important. The most important action an operator can take to prevent tire-related events is to maintain proper tire inflation pressure. Failure to keep aircraft tires properly inflated can lead to very serious consequences. The most serious of these is the structural failure of the tire. If the tire operates underinflated or over-deflected/over-loaded, the nylon cords which form the structure of the tire go in and out of compression as the tire rotates. This weakens the cords – much like a paperclip which is bent back and forth – until eventually the cords break. If enough cords break, the entire structure will eventually fail.
Figure 13. Compressive break in an interior ply.
This particular break damaged the inner liner, allowing air to migrate through the tire to the atmosphere. Another serious consequence of under-inflation is the thrown tread. Over-deflection increases shear between components in the tire as it rolls in and out of contact and deforms. This results in a more rapid build‐up of heat within the tire than would be evident if the tire were properly inflated. At some point the excessive heat will cause the rubber to revert, or reverse cure. This reverted rubber is like grease with no strength or adhesion to contain the structure. This can allow the tire to decompose, throwing the entire tread or pieces of it. In addition to destroying the tire, thrown treads often result in expensive aircraft damage.
Figure 14. Example of reversion.
Aircraft tires are designed and tested to “rated” conditions. These rated conditions are specified by industry standard’s bodies like The Tire and Rim Association (T&RA) and The European Tyre and Rim Technical Organization (ETRTO). However, most aircraft are not operated at the rated limits.This means that an operator must consult the aircraft’s Aircraft Maintenance Manual (AMM) or Pilot Operating Handbook (POH) to find out the recommended operating pressure range.
In order to ensure that an aircraft’s tires are properly inflated, Michelin recommends checking the inflation pressure, with a calibrated gauge, before the first flight of the day or before each flight if not flown daily. Because of the high pressures and extreme temperatures at which aircraft tires operate, they do not hold air perfectly. In fact, an aircraft tire can lose up to 5 percent of its pressure in 24 hours and still be perfectly serviceable.
It’s important to check tire pressures when they are cold if at all possible. Michelin recommends checking a tire’s pressure no sooner than three hours after it has last rolled. Tires that have rolled under load recently heat up, making it very difficult to determine what the proper pressure should be. Pilots and mechanics One may think that they can identify under-inflated tires by looking at them, hitting them with a bat, or looking at the wing height. In fact, it is impossible to look at tires and tell if they’re underinflated because, on a two-wheel gear, the properly inflated tire assumes more of the load than the under-inflated tire and both tires deflect the same amount.
Because the consequences of having improperly inflated tires can be so severe, the acceptable limits of operation are narrow. The chart in Figure 15 shows Michelin’s recommended actions when checking air pressures. The target pressure range is between 100 and 105 percent of the AMM-defined operating pressure. Michelin recommends always servicing the tires to the top of that range – 105 percent. If the pressure is found to be between 95 and 100 percent of operating pressure, service the tire to 105 percent; this is considered normal pressure loss. If it is between 90 and 95 percent, the pressure loss is no longer normal. Service the tire to 105 percent, make a log book entry, and recheck in 24 hours. If the pressure is again found to be in the 90 to 95 percent range, remove the tire and troubleshoot the reason for the pressure loss. If the tire has operated at less than 90 percent of the targeted operating pressure, it is no longer serviceable and must be removed. Tires that have operated under these conditions have been over-deflected to the point where the structure of the tire may be compromised. Finally, if a tire has operated at less than 80 percent of the operating pressure, it must be removed from service and so must its mate (on dual-wheel gears). In this case, the mate is most likely damaged as well.
Figure 15. Pressure Monitoring Action Chart.
Finally, when servicing tires, it is important to think about ambient temperature change. For every 5 F (3 C) change in temperature, there is a corresponding 1 percent change in tire pressure. If, for example, a tire is serviced in Miami where it is 85 F and the plane flies to Minneapolis where it is 25 F, a tire which was serviced to 100% of operating pressure, will be at 88 percent in Minneapolis (after cooling for three hours). If a mechanic checks the pressure in Minneapolis before the plane returns to Miami, the tire will be unserviceable and need to be changed.
This is another reason Michelin recommends servicing the tires to the top of the acceptable range (105 percent of operating pressure). If this same tire had been serviced to 105 percent in Miami, it would have been at 93 percent in Minneapolis and still serviceable. Improper tire pressure maintenance can have serious consequences for aircraft safety. One relatively easy way to help avoid those consequences is to check tire pressures regularly and service them, as necessary. Following these three actions is a good way to make sure you get the most value out of your tires and contribute to the safe operation of your aircraft:
[15] 787 braking system:
Stopping a 200-tonne aircraft landing at 180 mph requires a lot of braking force. To do this, the 787 has one brake unit on each of the eight wheels on the main gear assembly. On other aircraft types, the brake units are powered by the hydraulics system. An electrical signal is sent from the flight deck to hydraulic actuators near the main landing gear. Here, hydraulic fluid at 3,000 pound per square inch is used to force the brake unit against the wheel, thus slowing it down. This system works fine, but the pipes and actuators that form this part of the hydraulic system come at a considerable weight cost. Extra weight means more fuel burn, which in turn increases costs and carbon emissions. Hence, a more effective braking system is needed. Therefore, the use of the hydraulic system and all its associated architecture was replaced by the use of electricity to power the brakes.
When the pilots press on the brake pedals, an electrical signal is sent to the brake unit on the wheel. The electrically powered actuators are used to press the carbon brake disc against the wheel, thereby slowing it down. By changing to electric brakes, a 787-8 saves 141 pounds per aircraft and a 787-9 saves 245 pounds. The brakes are also known as “plug and play” because electrical wiring replaces the traditional hydraulics and it’s much easier and quicker to change the brake units when needed. Smart features also allow engineers to monitor the brake performance more closely, giving a real-time measurement of wear on the carbon disks.
Figure 16. 787 Dreamliner.
Electric braking system:
The brake system on the 787 Dreamliner is controlled by the pilots pressing the tops of the rudder pedals under their feet, demanding the rate of braking which they require. This sends an electronic signal to the Left and Right Brake System Control Units (BSCUs). These then send signals to the four Electronic Brake Actuator Controllers (EBAC) which control the rate of braking on the wheels. Each wheel has four Electric Brake Actuators (EBA), a kind of piston which presses against the carbon brake discs. The brake disks are made up of two parts. They have rotors. These rotors are connected to the wheel by drive tabs. As these drive tabs are in contact with the inside of the wheel, they spin at the same speed. Depending on the brake manufacturer, there are either four or five of these rotors on each brake assembly. The second part of the disks are the stators. These sit around each rotor and are fixed in place and thus are stationary. As the wheel turns, the rotors spin round inside the stators. When the brakes are applied, the four EBAs apply pressure to the first stator. This in turn squeezes the stationary stators up against the spinning rotors and it’s this friction which slows the wheel down.
Antiskid Protection:
When landing on slippery runways, there’s a chance that the wheels may start to skid as the brakes are applied. To stop this from happening and to maintain maximum effective braking, each wheel has anti-skid protection. Using a variety of sources to determine the aircraft speed, the brake units know how fast the wheels should be spinning. If that speed drops significantly, it’s because the current brake pressure on that wheel is too great and the wheel is just skidding over the surface. In this situation, the anti-skid system automatically reduces the braking on that wheel to a point where the skid stops before reapplying the pressure. All this is done in a fraction of a second.
Autobrake:
Pressing on the brakes is pretty straight forward when taxiing in a straight line at low speed. However, when landing in strong winds, it can be a little tricky. It is needed to use our feet on the rudder pedals to line the nose of the aircraft up with the runway centerline at the last moment. Then, whilst holding that position, slide our feet up to press the toe brakes which is not easy when moving at 160 mph. To help the aircraft get the braking underway as soon as touch down, autobrake system is used. This provides automatic braking at a preselected rate as soon as the aircraft senses that it is on the ground. It also provides full braking pressure in the case of a rejected takeoff if the speed is above 85 knots (98 mph).
Brake temperature indication:
With friction comes heat. As a result, each brake unit displays its temperature on the wheel synoptic page in the flight deck. The numerical values relating to brake temperature are shown next to each wheel. A value of 0-4.9 is in the normal range. When a temperature becomes 5.0 or above, an advisory message is displayed to the pilots. Should the brakes become too hot, there’s a chance that the heat transferred to the wheels could cause the tires to explode. To stop this from happening, when a certain temperature is reached, fuse plugs in the tires melt. This allows the air to be released safely and slowly deflate the tires.
Parking brake:
Very often it is needed to engage the brakes and keep them on. This is particularly useful on long taxis to the runway and obviously when parked at the gate. The park brake is set by fully pressing down both toe brakes and pulling the parking brake lever up. With this set, we can then release the pressure from the pedals. To release, we just press the brake pedals again.
In addition to the brakes, there are two other systems which help slow the aircraft down on landing. The spoilers and the reverse thrust.
Spoilers:
The large panels at the top of the wings which raise up on touch down are the called the spoilers as they literally spoil the airflow over the wing. This dumps any remaining lift the wings are generating, allowing the wheels to take all the weight and achieve maximum efficiency from the brakes.
Reverse thrust:
The final part of the braking process comes from reverse thrust. Just after the touched down, two levers are pulled on top of the thrust levers to engage the reverse thrust, a sort of “reverse gear” for jet engines. This causes blockers inside the engine to deploy and a door in the side of the engine to slide backward. The air which normally leaves the engine out the back is deflected forward by the blockers and out through the door.
With necessary assumptions, calculate the force and power required to push / pull an aircraft by a towing vehicle and develop the model for the calculated force and power using Simulink.
EXPLANATION AND OBSERVATION:
The following values are assumed to calculate the force and power required to push/pull the aircraft by a towing vehicle. The aircraft under consideration is Boeing 747-200. The maximum take-off weight of the given aircraft is 3,77,840 kg. But the aircraft authority doesn’t fill the aircraft to that weight abiding safety protocols. A wavier is applied to the weight as some percentage of the maximum take-off weight. Following are the assumptions made to calculate the force and power required to push/pull the aircraft by towing vehicle:
Let the of the aircraft i.e. Boeing 747-200 WA= 636klbs [16] = 288484.747 kg
Rolling resistance coefficient for the aircraft tyre i.e.,
Let the weight of the towing vehicle be WTV = 30000 kg
Rolling resistance coefficient for the towing vehicle tyre i.e.,
We know, the value of acceleration due to gravity i.e. g = 9.806 m/s2
Let the aircraft velocity while towing be V = 20 kmph = 5.556 m/s
Let the towing vehicle velocity while towing be VT = 6 m/s
Let the air density ρ = 1.1839 kg/m3 (at 25 oC)
Let the frontal area of the aircraft be A = 18 m2
Assuming the coefficient of the drag as CD = 0.0088 [16].
Let the overall diameter of the tyre of the towing vehicle having a tyre size of 10.00-22 [17] = 1130 mm = 1.13m
Therefore, the radius of the towing vehicle tyre is R = 0.565 m.
CALCULATING THE FORCES:
Rolling resistance due to aircraft (RRA ):
Rolling resistance due to towing vehicle (RRTV ):
The total Rolling resistance is given as (RR):
The drag force exerted while taxiing the aircraft:
Therefore, to obtain the total force required to pushback the aircraft, it is required to consider the effect of rolling resistance due to aircraft and the towing vehicle along with the drag force exerted while taxiing the aircraft. It is mathematically expressed as:
The torque required by the towing vehicle to perform the operation of push/pull on the aircraft is given by:
The power required by the towing vehicle to perform the operation of push/pull on the aircraft is given by:
The above calculation can be performed in SIMULINK as follows:
Figure 17. Layout of the SIMULINK model of Calculation of the force and power required to push/pull the aircraft by a towing vehicle.
Design an electric powertrain with type of motor, it’s power rating, and energy requirement to fulfill aircraft towing application in Simulink. Estimate the duty cycle range to control the aircraft speed from zero to highest. Make all required assumptions. Prepare a table of assumed parameters. Draw a block diagram of powertrain. (Hint :DC7 Block)
EXPLANATION AND OBSERVATION:
In terms of kWhr,
Figure 18. Layout of two-Quadrant chopper in Simulink.
Parameter |
Value/Specification |
Resistance Ron |
0.001 ohms |
Forward Voltage Vf |
1 V |
Snubber resistance Rs |
1e5 ohms |
Snubber capacitance Cs |
Inf F |
Table 4. Predefined parameters for IGBT.
Parameter |
Value/Specification |
Pulse type |
Time based |
Time (t) |
Simulation time |
Amplitude |
1 |
Period |
0.002 seconds |
Pulse width (% of period) |
75 |
Phase delay |
0 |
Table 5. Predefined parameters for Pulse generator block.
Parameter |
Value/Specification |
Resistance Ron |
0.001 ohms |
Forward Voltage Vf |
0.8 V |
Snubber resistance Rs |
inf ohms |
Snubber capacitance Cs |
0 F |
Table 6. Predefined parameters for Diode.
Parameter |
Value/Specification |
Model |
17: 150HP 500V 1750RPM Field:300V |
Mechanical Input |
Torque TL |
Initial Speed |
0.001 rad/sec |
Sample time(-1 for inherited) |
-1 |
Table 7. Parameters that are predefined for the DC Machine.
Q1 current, Q2 current, D1 current, D2 current; Q1 voltage, Q2 voltage, D1 voltage, D2 voltage.
Results of DC motor under consideration. The green plot indicates electromechanical torque, and the red curve indicates the angular velocity. The yellow curve indicates the armature current, and the blue curve indicates the field current.
The output of the Simulink model gives the maximum value of electromechanical torque as 1300 Nm. Where as the value of the corresponding angular velocity is 81.68 rad/sec. We know that the power developed is given by the following formula:
Therefore, the total power developed at maximum torque condition is 106.184 kW which is achieved at 0.077 seconds from the start of the EV. The value of the power developed is slightly greater than the power required to tow the aircraft as the power rating required was of 139 HP but the vehicle under consideration has 150 HP motor. The difference in power required and developed is obvious.
To estimate the duty cycle:
Input power is the power developed by the EV which is 106.184 kW and the output power is the power required to tow the aircraft which is 103.6221 kW.
Therefore, the duty cycle is calculated as follows:
The duty cycle ratio obtained is 97.58% which effectively high. This might not be the case in the practical applications.
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